3[6-(y+2)]=

Solution for 3[6-(y+2)]= equation:

Simplifying
3[6 + -1(y + 2)] = 0

Reorder the terms:
3[6 + -1(2 + y)] = 0
3[6 + (2 * -1 + y * -1)] = 0
3[6 + (-2 + -1y)] = 0

Combine like terms: 6 + -2 = 4
3[4 + -1y] = 0
[4 * 3 + -1y * 3] = 0
[12 + -3y] = 0

Solving
12 + -3y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -3y = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -3y = 0 + -12
-3y = 0 + -12

Combine like terms: 0 + -12 = -12
-3y = -12

Divide each side by '-3'.
y = 4

Simplifying
y = 4